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Computable Euclid

Proposition 7

Theorem

If a line segment AB  is divided into any two parts at point C, then 2 AB CB  + AC 2 = AB 2 + CB 2.

Commentary

1. Let AB  be the given line segment, and let C be any point on AB .
2. On AB , construct a square ABDE.
3. Find a point G on ED  such that CG  is parallel to the side AE  of the square, and intersects the diagonal BE  at a point F.
4. Through F, draw a line HK  that is parallel to AB .
5. The rectangle ABKH has been constructed with the area equal to that of rectangle CBDG.
6. The sum of the areas of rectangles ABKH (AB CB ), CBDG (AB CB ), and square HFGE (AC 2) is equal to the sum of the areas of the two squares: ABDE (AB 2) and CBKF (CB 2).
7. This geometric relationship can be expressed algebraically as follows: if x = y + z, then 2 x z + y2 = x2 + z2 (where AB  = x, AC  = y and CB  = z). This algebraic relationship is a polynomial identity.

Original statement

ἐὰν ϵὐθϵῖα γραμμὴ τμηθῇ, ὡς ἔτυχϵν, τὸ ἀπὸ τῆς ὅλης καὶ τὸ ἀϕ᾽ ἑνὸς τῶν τμημάτων τὰ συναμϕότϵρα τϵτράγωνα ἴσα ἐστὶ τῷ τϵ δὶς ὑπὸ τῆς ὅλης καὶ τοῦ ϵἰρημένου τμήματος πϵριϵχομένῳ ὀρθογωνίῳ καὶ τῷ ἀπὸ τοῦ λοιποῦ τμήματος τϵτραγώνῳ.

English translation

If a straight line is cut at random, the square on the whole and that on one of the segments both together are equal to twice the rectangle contained by the whole and the said segment and the square on the remaining segment.


Computable version


Additional instances


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